Completed part 2
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@@ -1,12 +1,11 @@
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#include "Utils.h"
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#include "TDoublyLinkedList.h"
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#include "TStack.h"
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#include "TPerson.h"
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#include <ctime>
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#include <iostream>
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#include <limits>
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#include "TDoublyLinkedList.h"
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#include "TStack.h"
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#include <numbers>
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int Utils::Choice()
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{
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@@ -15,7 +14,6 @@ int Utils::Choice()
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int choice;
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std::cin >> choice;
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std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
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//std::cout << "\n=====================\n";
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return choice;
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}
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@@ -89,5 +87,78 @@ int Utils::RandomInt(const int min, const int max)
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if (max <= min)
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return 0;
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return min + rand() % (max - min + 1); // <---- Limited randomness, but again
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return min + rand() % (max - min + 1); // <---- Limited randomness, but again
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} // sufficient for this use case
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bool Utils::CompareLastnames(const TPerson *a, const TPerson *b)
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{
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if (a->cabinSize < b->cabinSize)
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return true;
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if (a->cabinSize > b->cabinSize)
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return false;
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return a->lastName < b->lastName;
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}
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int Utils::Partition(TPerson **arr, const int startIndex, const int endIndex)
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{
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TPerson *pivot = arr[endIndex];
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int i = startIndex - 1;
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for (int j = startIndex; j < endIndex; j++) {
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if (CompareLastnames(arr[j], pivot)) {
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i++;
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std::swap(arr[i], arr[j]);
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}
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}
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std::swap(arr[i + 1], arr[endIndex]);
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return i + 1;
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}
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/// Time complexity **on average** is O(n log n) but worst case it O(n^2)
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/// depending on where in the range the pivot lands -- If pivot is at either extreme
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/// the algorithm has to search through the entire list for every value it sorts -- n^2
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/// However it does sort in-place, meaning no extra memory is needed
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void Utils::QuickSort(TPerson** arr, const int low, const int high)
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{
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if (low < high) {
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int p = Partition(arr, low, high);
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QuickSort(arr, low, p - 1);
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QuickSort(arr, p + 1, high);
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}
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}
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/// Time complexity of the binary search is O(log n)
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/// However the included fallback search is O(n)
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int Utils::BinarySearch(TPerson** arr, int p1, int p2, const std::string &target)
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{
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const int origStart = p1;
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const int origEnd = p2;
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while (p1 <= p2) {
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const int newP = (p1 + p2) / 2;
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std::string currentFirst = arr[newP]->firstName;
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std::string currentLast = arr[newP]->lastName;
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if (target == currentFirst || target == currentLast)
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return newP;
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if (target > currentLast)
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p1 = newP + 1;
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else
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p2 = newP - 1;
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}
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/// Extra to search for firstname in the event that no matches were found
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/// Disregard this section if you're purely looking at the
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/// binary search understanding and implementation
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for (int i = origStart; i <= origEnd; i++) {
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if (arr[i]->firstName == target)
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return i;
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}
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return -1;
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}
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